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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude1664 × 1.75 + 1008 × 1.25 – 1220 × 0.65 = x
Correct
Answer: 4.3379
Explanation
x = 2912 + 1260 – 793 = 3379Incorrect
Answer: 4.3379
Explanation
x = 2912 + 1260 – 793 = 3379 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude830 ÷ 16 – 34.09% of 450.03 + 44.99% of 280 = x
Correct
Answer : 1.25
Explanation
52 – 153 + 126 = 25Incorrect
Answer : 1.25
Explanation
52 – 153 + 126 = 25 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude8, 8, 14, 38, 98 ?
Correct
Answer : 2.218
Explanation
8 + (1³ – 1) = 8
8 + (2³ – 2) = 14
14 + (3³ – 3) = 38
38 + (4³ – 4) = 98
98 + (5³ – 5) = 218Incorrect
Answer : 2.218
Explanation
8 + (1³ – 1) = 8
8 + (2³ – 2) = 14
14 + (3³ – 3) = 38
38 + (4³ – 4) = 98
98 + (5³ – 5) = 218 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative Aptitude21, 35, 56, 91, 154 ?
Correct
Answer : 1.273
Explanation
21 × 2 – 7 = 35
35 × 2 – 14 = 56
56 × 2 – 21 = 91
91 × 2 – 28 = 154
154 × 2 – 35 = 273Incorrect
Answer : 1.273
Explanation
21 × 2 – 7 = 35
35 × 2 – 14 = 56
56 × 2 – 21 = 91
91 × 2 – 28 = 154
154 × 2 – 35 = 273 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative Aptitudeten years ago Ankit was half of Ramesh in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
Correct
Answer: 2.35
Explanation
Let Ankit’s age 10 years ago = x years.
Then, Ramesh’s age 10 years ago = 2x years.
(x + 10) / (2x+ 10) = 3/4
=> x = 5.
So, the total of their present ages = (x + 10 + 2x + 10)
= (3x + 20) = 35 years.Incorrect
Answer: 2.35
Explanation
Let Ankit’s age 10 years ago = x years.
Then, Ramesh’s age 10 years ago = 2x years.
(x + 10) / (2x+ 10) = 3/4
=> x = 5.
So, the total of their present ages = (x + 10 + 2x + 10)
= (3x + 20) = 35 years. 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe average weight of 18 men is 50 kg. A new man replaced an old man whose weight is 45 kg. Hence, the average weight of the men increased by 1 kg. What is the ratio between the old man and new man?
Correct
Answer :3.5:7
Explanation
Incorrect
Answer :3.5:7
Explanation

Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe length and breadth of a rectangular lawn are 36 m and 20 m respectively. It has two roads, each 3m wide and one parallel to the breadth and the other parallel to the length. What is the cost of gravelling the two roads at the rate of Rs. 38?
Correct
Answer:3.Rs. 6042
Explanation
Length and breadth of rectangular lawn = 36 m and 20 m.
Area of the path = 36*3 + 20 * 3 – (3*3) = 159 sq. cm
Cost of gravelling the path = 159 * 38 = Rs. 6042.Incorrect
Answer:3.Rs. 6042
Explanation
Length and breadth of rectangular lawn = 36 m and 20 m.
Area of the path = 36*3 + 20 * 3 – (3*3) = 159 sq. cm
Cost of gravelling the path = 159 * 38 = Rs. 6042. 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThree types of pulses are mixed together. Their volumes are in a proportion to 5, 4 and 3 respectively and the weights of equal volumes are in proportion to 6, 5 and 4 respectively. What is the weight of the pulse of first type if the weight of the mixture is 248 kg?
Correct
Answer: 1. 120 kg
Explanation
Incorrect
Answer: 1. 120 kg
Explanation

Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA, B and C started a business with their investments in the ratio 1:2:4. After 6 months A invested the half amount more as before and B invested twice the amount as before while C withdraw 1/4th of their investments. Find the ratio of their profits at the end of the year.
Correct
Answer : 3.5:12:14
Explanation
Incorrect
Answer : 3.5:12:14
Explanation

Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA sum of money amount to Rs.944 in 3 years at simple interest. If the rate Of interest be raised by 25% the sum amounts to 980 during the same period.
Find the sum and rate of interest.Correct
Answer :2 . Rs.800, 6%
Explanation
Incorrect
Answer :2 . Rs.800, 6%
Explanation
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